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X^2+14X=159
We move all terms to the left:
X^2+14X-(159)=0
a = 1; b = 14; c = -159;
Δ = b2-4ac
Δ = 142-4·1·(-159)
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-8\sqrt{13}}{2*1}=\frac{-14-8\sqrt{13}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+8\sqrt{13}}{2*1}=\frac{-14+8\sqrt{13}}{2} $
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